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Exam code:C300

Linear simultaneous equations

What are linear simultaneous equations?

  • When there are two unknowns (x and y), we need two equations to find them both

    • For example, 3+ 2y = 11 and 2x= 5

      • The values that work are x = 3 and y = 1

  • These are called linear simultaneous equations

    • Linear because there are no terms like x2 or y2 

How do I solve linear simultaneous equations by elimination?

  • Elimination removes one of the variables, or y

  • To eliminate the x‘s from 3x + 2y = 11 and 2x – = 5, make the number in front of the x (the coefficient) in both equations the same (the sign may be different)

    • Multiply every term in the first equation by 2

      • 6x + 4y = 22

    • Multiply every term in the second equation by 3

      • 6– 3y = 15

    • Subtracting the second equation from the first eliminates x

      • When the sign in front of the term you want to eliminate is the same, subtract the equations

negative bottom enclose table row cell 6 x plus 4 y equals 22 end cell row cell 6 x minus 3 y equals 15 end cell end table end enclose
space space space space space space space space space space space space space 7 y equals 7

  • The y terms have become 4– (-3y) = 7(be careful with negatives

    • Solve the resulting equation to find y

    • = 1

  • Then substitute = 1 into one of the original equations to find x

    • 3x + 2 = 11, so 3= 9, giving x = 3

  • Write out both solutions together, = 3 and = 1

  • Alternatively, you could have eliminated the y‘s from 3+ 2= 11 and
    2= 5 by making the coefficient of y in both equations the same 

    • Multiply every term in the second equation by 2

    • Adding this to the first equation eliminates y (and so on)

      • When the sign in front of the term you want to eliminate is different, add the equations

plus bottom enclose table row cell 3 x plus 2 y equals 11 end cell row cell 4 x minus 2 y equals 10 end cell end table end enclose space
space space space space 7 x space space space space space space space space space equals 21

How do I solve linear simultaneous equations by substitution?

  • Substitution means substituting one equation into the other

    • This is an alternative method to elimination

      • You can still use elimination if you prefer

  • To solve 3x + 2= 11 and 2x – y = 5 by substitution

    • Rearrange one of the equations into y = … (or = …)

      • For example, the second equation becomes y = 2x – 5 

    • Substitute this into the first equation

      • This means replace all y‘s with 2x – 5 in brackets

      • 3x + 2(2x – 5) = 11

    • Solve this equation to find x

      • x = 3

    • Then substitute x = 3 into y = 2x – 5 to find y

      • = 1

How do I solve linear simultaneous equations graphically?

  • Plot both equations on the same set of axes

    • To do this, you can use a table of values

      • or rearrange into y = mx + c if that helps

  • Find where the lines intersect (cross over)

    • The and solutions to the simultaneous equations are the and coordinates of the point of i

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