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Maths Gcse Wjec-Eduqas Higher

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  1. Scatter-Graphs-And-Correlation Wjec-Eduqas Higher
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  48. Completing-The-Square Wjec-Eduqas Higher
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  52. Introduction-To-Algebra Wjec-Eduqas Higher
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  58. Percentages Wjec-Eduqas Higher
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  59. Fractions Wjec-Eduqas Higher
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  60. Powers-Roots-And-Standard-Form Wjec-Eduqas Higher
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  61. Prime-Factors-Hcf-And-Lcm- Wjec-Eduqas Higher
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  62. Number-Operations Wjec-Eduqas Higher
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Exam code:C300

Distance-time graphs

How do I use a distance-time graph?

  • Distance-time graphs show the distance travelled at different times

    • Distance is on the vertical axis

    • Time is on the horizontal axis 

  • The gradient of the graph is the speed

    • speed space equals space distance over time space equals space rise over run

  • The steeper the line the faster the object is moving

    • Lines with positive gradients represent objects moving away from the start point

    • Lines with negative gradients represent objects moving towards the start point

    • Lines that are horizontal represent rest

      • The object is stationary (not moving)

How do I work out the overall average speed?

  • For journeys with multiple parts

    • the overall average speed for the whole journey is fraction numerator total space distance space travelled over denominator total space time end fraction

    • The total time includes any rests

Examiner Tips and Tricks

These questions often have a lot of parts that depend on each other, so always double check each answer before continuing.

Worked Example

One afternoon, Mary cycled 8 km from her home to her grandfather’s house.
Part of the travel graph for her journey is shown. 

A distance time graph

 (a) Find Mary’s speed at 2 pm.

The speed is the gradient of the line at that point
The gradient at 2pm is the same as the gradient for all points between 1:45pm and 2:45pm
It is easiest to use rise over run for that bigger section

rise over run equals 6 over 1

6 km/h

(b) Calculate, in minutes, how long Mary stopped on the way to her grandfather’s house.

The horizontal line is where Mary stops
The scale is 1 square = 15 minutes

15 minutes

(c) Calculate Mary’s overall average speed from leaving her home to arriving at her grandfather’s house, giving your answer correct to 3 significant figures.

 Overall average speed is fraction numerator total space distance space travelled over denominator total space time end fraction 

Total distance travelled is 8 km
Total time (including rests) is 1.75 hours

<img alt=”fraction numerator 8 over denominator 1.75 end fraction equals 4.57142…” data-mathml='<math ><semantics><mrow><mfrac ><mn>8</mn><mrow><mn>1</mn><mo>.</mo><mn>75</mn></mrow></mfrac><mo >=</mo><mn g

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