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Exam code:C300
Solving by completing the square
How do I solve a quadratic equation by completing the square?
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To solve x2 + bx + c = 0
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replace the first two terms, x2 + bx, with (x + p)2 – p2 where p is half of b
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This is completing the square
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x2 + bx + c = 0 becomes (x + p)2 – p2 + c = 0
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(where p is half of b)
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rearrange this equation to make x the subject (using ±√)
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For example, solve x2 + 10x + 9 = 0 by completing the square
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x2 + 10x becomes (x + 5)2 – 52
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so x2 + 10x + 9 = 0 becomes (x + 5)2 – 52 + 9 = 0
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make x the subject (using ±√)
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(x + 5)2 – 25 + 9 = 0
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(x + 5)2 = 16
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x + 5 = ±√16
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x + 5 = ±4
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x = -5 ±4
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x = -1 or x = -9
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It also works with numbers that lead to surds
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The answers found will be in exact (surd) form
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Examiner Tips and Tricks
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When making x the subject to find the solutions, don’t expand the squared bracket back out again!
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Remember to use ±√ to get two solutions
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How do I solve by completing the square when there is a coefficient in front of the x2 term?
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If the equation is ax2 + bx + c = 0 with a number (other than 1) in front of x2
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you can divide both sides by a first (before completing the square)
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For example 3x2 + 12x + 9 = 0
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Divide both sides by 3
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x2 + 4x + 3 = 0
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Complete the square on this easier equation
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This trick only works when completing the square to solve a quadratic equation
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i.e. it has an “=0” on the right-hand side
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Don’t do this when using completing the square to rewrite a quadratic expression in a new form
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i.e. when there is no “=0”
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For that, you must factorise out the a (but not divide by it)
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and so on
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How does completing the square link to the quadratic formula?
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The quadratic formula actually comes from completing the square to solve ax2 + bx + c = 0
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a, b and c are left as letters when completing the square
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This makes it as general as possible
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You can see hints of this when you solve quadratics
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For example, solving x2 + 10x + 9 = 0
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by completing the square, (x + 5)2 = 16 so x = -5 ± 4 (as above)
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by the quadratic formula,
= -5 ± 4 (the same structure)
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Worked Example
Solve <img alt=”2 x squared minus 8 x minus 24 equals 0″ data-mathml='<math ><semantics><mrow><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>8</mn><mi>x</mi><mo>-</mo><mn>24</mn><mo>=</mo><mn>0</mn></mrow><annotation encoding=”application/vnd.wiris.mtweb-params+json”>{“language”:”en”,”fontFamily”:”Times New Roman”,”fontSize”:”18″,”autoformat”:true}</annotation></semantics></math>’ height=”23″ role=”math” src=”data:image/svg+xml;charset=utf8,%3Csvg%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20xmlns%3Awrs%3D%22http%3A%2F%2Fwww.wiris.com%2Fxml%2Fmathml-extension%22%20height%3D%2223%22%20width%3D%22124%22%20wrs%3Abaseline%3D%2217%22%3E%3C!–MathML%3A%20%3Cmath%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmsup%3E%3Cmi%3Ex%3C%
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