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Problem-Solving-With-Volumes Wjec-Eduqas Foundation
Exam code:C300
Problem-solving with volumes
What is problem-solving?
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Problem-solving, usually has two key features:
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A question is given as a real-life scenario
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eg. The volume of water in a swimming pool…
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There is usually more than one topic of maths you will need in order to answer the question
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eg. Volume and money
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What are common problems that involve volume?
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Volume is a commonly used topic of ‘real-world’ maths
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For example, a carton of juice in the shape of a cuboid, a cylindrical tin and a triangular prism chocolate box all involve volume
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Typically, the ‘real-world’ scenarios also have a cost
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A lot of volume problems also involve calculations with money
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How do I solve problems involving volume?
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Often the 3D object in a question will not be a standard cuboid, cone, sphere, etc.
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It will likely either be:
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A prism (3D shape with the same cross-section running through it)
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A portion or fraction of a standard shape (a hemisphere for example)
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A compound object (an object made up of two or more standard 3D objects)
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If the object is a prism, recall that the volume of a prism is the cross-sectional area × its length
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The cross-sectional area may be a compound 2D shape
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For example, an L-shape, or a combination of a rectangle and a triangle
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If the object is a fraction of a standard shape, consider the “full” version of the object and find the appropriate fraction of it
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A hemisphere is half a sphere
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If the object is a compound object, find the volumes of the individual standard 3D objects and add them together
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Problem solving questions could appear on either a non-calculator paper or a calculator paper
Examiner Tips and Tricks
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Before you start calculating, make a quick note of your plan to tackle the question
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For example, “Find the area of the triangle and the rectangle, add together, multiply by the length”
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Worked Example
The diagram shows a prism.

Work out the volume of the prism.
The volume is the area of the cross section × length (10 cm)
Find the area by splitting into a 7 × 4 and a (9 – 4) × 2 rectangle (or a 9 × 2 and a (7 – 2) × 4 rectangle)
7 × 4 + (9 – 4) × 2 = 38 cm2
Find the volume (by multiplying 38 by 10)
38 × 10
380 cm3
Responses