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Exam code:C300

Types of sequences

What types of sequences are there?

  • Linear sequences are the sequences that you are most likely to see in an exam question

    • These are sometimes called arithmetic sequences or progressions

    • A common difference is added to or subtracted from one term to get to the next term

  • Other types of sequences that you may also come across include

    • Quadratic sequences (square numbers)

    • Cube numbers

    • Triangular numbers

    • Geometric sequences

    • Fibonacci sequences

  • Another common type of sequence in exam questions, is fractions with combinations of the above

    • Look for anything that makes the position-to-term and/or the term-to-term rule easy to spot

SeqOth Notes fig2, downloadable IGCSE & GCSE Maths revision notes

What is a quadratic sequence?

  • A quadratic sequence is based around square numbers

  • The second differences are constant (the same)

    • Second differences are the differences between the first differences

    • For example, 2, 3, 6, 11, 18, …
      1st Differences: 1 3 5 7

      2nd Differences: 2 2 2

What is a geometric sequence? 

  • A geometric sequence can also be referred to as a geometric progression and sometimes as an exponential sequence

  • In a geometric sequence, the term-to-term rule would be to multiply by a constant

  • This multiplier is called the common ratio and can be found by dividing any two consecutive terms

    • Consider the sequence 4, 8, 16, 32, 64, …
      The common ratio would be x2 (8 ÷ 4 or 16 ÷ 8 or 32 ÷ 16 and so on)

      SeqOth Notes fig3, downloadable IGCSE & GCSE Maths revision notes

What is a Fibonacci sequence? 

  • THE Fibonacci sequence is 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, …

  • The sequence starts with the first two terms as 1

  • Each subsequent term is the sum of the previous two

    • Notice that two terms are needed to start a Fibonacci sequence

  • Any sequence that has the term-to-term rule of adding the previous two terms is called a Fibonacci sequence but the first two terms will not both be 1

  • Fibonacci sequences occur a lot in nature such as the number of petals of flowers

 

SeqOth Notes fig4, downloadable IGCSE & GCSE Maths revision notes

Problem solving with sequences

  • When the type of sequence is known it is possible to find unknown terms within the sequence

  • Possibly simultaneous equationsThis can lead to problems involving setting up and solving equations

  • Other problems may involve sequences that are related to common number sequences such as square numbers, cube numbers and triangular numbers

 

SeqOth Notes fig5, downloadable IGCSE & GCSE Maths revision notes

Worked Example

(a)

Identify the types of sequence below;

i) 4, 5, 9, 14, 23, 37, 60, …

There is no common second difference so it is not quadratic

There is no common ratio so it is not geometric

Two terms add together to give the next term in the sequence

4 + 5 = 9

5 + 9 = 14 etc.

Fibonacci sequence 

ii) 6, 10, 16, 24, 34, …

First differences are not equal so it is not linear

Second differences are equal

6, 10, 16, 24, 34, …

4 6 8 10

2 2 2

Quadratic sequence

iii) 12, 7, 2, -3, …

There is a common first difference

12, 7, 2, -3, …

-5 -5 -5

Linear sequence

 

(b) The 3rd and 6th terms in a Fibonacci sequence are 7 and 31 respectively.

Find the 1st and 2nd terms of the sequence.

Write down the terms of the sequence that you know in their correct position

n

1

2

3

4

5

6

an

 

 

7

 

 

31

We’re told that this is a Fibonacci sequence, so two consecutive terms added together give the next term

Let the second term, a2 be x
We can write an expression for the 4th term by adding together the second and 3rd terms
We can write an expression for the 5th term by adding together the 3rd and 4th terms

n

1

2

3

4

5

6

an

 

x

7

x + 7

(x + 7) + 7

31

We know that the 6th term in the sequence is 31

Add together the expressions for the 4th and the 5th term and set it equal to 31

(x + 7) + (x + 7) + 7 = 31

Simplify

2x + 21 = 31

Solve for x

2x = 10
x = 5

Substitute the value for x into the terms of the sequence that you have expressions for

<td

n

1

2

3

4

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