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Distance-Time-Graphs Wjec-Eduqas Foundation
Exam code:C300
Distance-time graphs
How do I use a distance-time graph?
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Distance-time graphs show the distance travelled at different times
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Distance is on the vertical axis
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Time is on the horizontal axis
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The gradient of the graph is the speed
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The steeper the line the faster the object is moving
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Lines with positive gradients represent objects moving away from the start point
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Lines with negative gradients represent objects moving towards the start point
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Lines that are horizontal represent rest
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The object is stationary (not moving)
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How do I work out the overall average speed?
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For journeys with multiple parts
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the overall average speed for the whole journey is
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The total time includes any rests
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Examiner Tips and Tricks
These questions often have a lot of parts that depend on each other, so always double check each answer before continuing.
Worked Example
One afternoon, Mary cycled 8 km from her home to her grandfather’s house.
Part of the travel graph for her journey is shown.

(a) Find Mary’s speed at 2 pm.
The speed is the gradient of the line at that point
The gradient at 2pm is the same as the gradient for all points between 1:45pm and 2:45pm
It is easiest to use for that bigger section
6 km/h
(b) Calculate, in minutes, how long Mary stopped on the way to her grandfather’s house.
The horizontal line is where Mary stops
The scale is 1 square = 15 minutes
15 minutes
(c) Calculate Mary’s overall average speed from leaving her home to arriving at her grandfather’s house, giving your answer correct to 3 significant figures.
Overall average speed is
Total distance travelled is 8 km
Total time (including rests) is 1.75 hours
<img alt=”fraction numerator 8 over denominator 1.75 end fraction equals 4.57142…” data-mathml='<math ><semantics><mrow><mfrac ><mn>8</mn><mrow><mn>1</mn><mo>.</mo><mn>75</mn></mrow></mfrac><mo >=</mo><mn g
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