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Reverse-Percentages Wjec-Eduqas Foundation
Exam code:C300
Reverse percentages
What is a reverse percentage?
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A reverse percentage question is one where we are given the value after a percentage increase or decrease and asked to find the value before the change
How do I solve reverse percentage questions?
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You should think about the before quantity
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even though it is not given in the question
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Find the percentage change as a multiplier, p
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This is the decimal equivalent of a percentage change
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A percentage increase of 4% means p = 1 + 0.04 = 1.04
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A percentage decrease of 5% means p = 1 – 0.05 = 0.95
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Use before × p = after to write an equation
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Get the order right: the percentage change happens to the “before”, not to the “after”
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Rearrange the equation to make the “before” quantity the subject
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Divide the “after” quantity by the multiplier, p
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What is a common mistake with reverse percentage questions?
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Here is an example: a price of a mobile increases by 10% to £220
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To find the price before, you do not apply a 10% decrease to £220
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That would give 220
0.9 = £198 (incorrect)
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Use before × p = after instead
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before
1.1 = 220
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before =
= £200 (correct)
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You cannot turn a percentage increase into a decrease with reverse percentage questions
Examiner Tips and Tricks
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To spot a reverse percentage question, see if you are being asked to find a quantity in the past
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Find the old / original / before amount …
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Worked Example
Jennie has been working for a company for the last ten years.
She receives a pay rise of 5%.
Her new salary is £31 500 per year.
Find her salary before the pay rise.
Use “before” × p = “after” to write an equation
The “before” amount is unknown and the “after” amount is 31 500
“before” × 1.05 = 31 500
Find the multiplier, p (by writing 5% as a decimal and adding it to 1)
p = 1 + 0.05 = 1.05
Find the value of “before” (by dividing both sides by 1.05)
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