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Maths Gcse Edexcel Higher

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  1. Scatter-Graphs-And-Correlation Edexcel Higher
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  2. Cumulative-Frequency-And-Box-Plots Edexcel Higher
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  3. Histograms Edexcel Higher
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  4. Statistical-Diagrams Edexcel Higher
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  5. Averages-Ranges-And-Data Edexcel Higher
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  9. Transformations Edexcel Higher
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  10. Vectors Edexcel Higher
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  11. 3D-Pythagoras-And-Trigonometry Edexcel Higher
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  12. Sine-Cosine-Rule-And-Area-Of-Triangles Edexcel Higher
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  14. Area-And-Volume-Of-Similar-Shapes Edexcel Higher
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  15. Congruence-Similarity-And-Geometrical-Proof Edexcel Higher
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  16. Volume-And-Surface-Area Edexcel Higher
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  17. Circles-Arcs-And-Sectors Edexcel Higher
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  18. Area-And-Perimeter Edexcel Higher
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  19. Circle-Theorems Edexcel Higher
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  20. Bearings-Scale-Drawing-Constructions-And-Loci Edexcel Higher
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  22. Symmetry-And-Shapes Edexcel Higher
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  23. Exchange-Rates-And-Best-Buys Edexcel Higher
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  24. Standard-And-Compound-Units Edexcel Higher
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  25. Direct-And-Inverse-Proportion Edexcel Higher
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  26. Problem-Solving-With-Ratios Edexcel Higher
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  27. Ratios Edexcel Higher
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  28. Sequences Edexcel Higher
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  29. Transformations-Of-Graphs Edexcel Higher
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  30. Graphing-Inequalities Edexcel Higher
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  31. Solving-Inequalities Edexcel Higher
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  32. Real-Life-Graphs Edexcel Higher
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  33. Estimating-Gradients-And-Areas-Under-Graphs Edexcel Higher
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  34. Equation-Of-A-Circle Edexcel Higher
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  35. Graphs-Of-Functions Edexcel Higher
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  36. Linear-Graphs Edexcel Higher
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  37. Coordinate-Geometry Edexcel Higher
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  38. Functions Edexcel Higher
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  39. Forming-And-Solving-Equations Edexcel Higher
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  40. Iteration Edexcel Higher
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  41. Simultaneous-Equations Edexcel Higher
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  42. Quadratic-Equations Edexcel Higher
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  43. Linear-Equations Edexcel Higher
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  44. Algebraic-Proof Edexcel Higher
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  46. Algebraic-Fractions Edexcel Higher
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  50. Algebraic-Roots-And-Indices Edexcel Higher
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  51. Introduction Edexcel Higher
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  52. Using-A-Calculator Edexcel Higher
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  53. Surds Edexcel Higher
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  54. Rounding-Estimation-And-Bounds Edexcel Higher
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  55. Fractions-Decimals-And-Percentages Edexcel Higher
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  56. Simple-And-Compound-Interest-Growth-And-Decay Edexcel Higher
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  57. Percentages Edexcel Higher
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  58. Fractions Edexcel Higher
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  59. Powers-Roots-And-Standard-Form Edexcel Higher
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  60. Prime-Factors-Hcf-And-Lcm Edexcel Higher
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  61. Number-Operations Edexcel Higher
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Exam code:1MA1

Percentage increases & decreases

How do I increase by a percentage?

  • A percentage increase makes an amount bigger by adding that percentage on to itself

  • Without a calculator, use the basic percentages methods to find the percentage you are increasing by

    • Then add this on to the original amount 

    • To increase 30 by 10%

      • 10% of 30 is 3

      • 30 + 3 = 33

      • This is equivalent to finding 110% of 30

  • With a calculator it is more efficient to use multipliers

    • A multiplier is the decimal equivalent of a percentage

      • percentage can be converted to a decimal by dividing by 100

    • When increasing by a percentage, we are finding a percentage greater than 100%

    • To increase 80 by 15%

      • We are finding 115% of 80, so the multiplier is 1.15

      • 1.15 × 80 = 92

How do I decrease by a percentage?

  • A percentage decrease makes an amount smaller by subtracting that percentage from itself

  • Without a calculator, use the methods outlined in Basic Percentages to find the percentage you are decreasing by

    • Then subtract this from the original amount 

    • To decrease 30 by 10%

      • 10% of 30 is 3

      • 30 – 3 = 27

      • This is equivalent to finding 90% of 30

        • Because 100% – 10% = 90%

  • With a calculator it is more efficient to use multipliers

    • When decreasing by a percentage, we are finding a percentage smaller than 100%

    • To decrease 80 by 15%

      • We are finding 85% of 80, so the multiplier is 0.85

        • Because 100% – 15% = 85%

      • 0.85 × 80 = 68

Worked Example

(a) Increase 200 kg by 21%.

Method 1: Non-calculator

By first finding 10% and 1%, find 21% of 200

10% of 200 = 20
1% of 200 = 2
21% of 200 = 20 + 20 + 2 = 42 

Add this to the original amount

200 + 42

242 kg

Method 2: Calculator

An increase by 21% is equivalent to finding 121% of the original amount
So the multiplier is 1.21 

1.21 × 200

242 kg

(b) An item that costs £ 500 is discounted by 35%.

Find the new price of the item.

A discount of 35% means the price decreases by 35%

Method 1: Non-calculator

By first finding 10% and 5%, find 35% of 500 

10% of 500 = 50
5% of 500 = 25
35% of 500 = 50 + 50 + 50 + 25 = 175 

Subtract this from the original amount

500 – 175

£325

Method 2: Calculator

A decrease of 35% is equivalent to finding 65% of the original amount (100 – 35 = 65) 
So the multiplier is 0.65

500 × 0.65

£ 325 

How do I deal with repeated percentage changes?

  • In some problems there may be several changes by a percentage

  • For example,

    • A shop increases the price of a product costing £80 by 10%,

      • equivalent to a multiplier of × 1.10

    • and then discounts the product by 15%,

      • equivalent to a multiplier of × 0.85

    • and then discounts the product by a further 20%

      • equivalent to a multiplier of × 0.80

  • You can either:

    • Multiply the starting amount by each multiplier in turn

      • ( ( ( 80 × 1.10 ) × 0.85 ) × 0.80 ) = £59.84

    • Or combine the multipliers first and then multiply by the “combined multiplier”

      • 1.10 × 0.85 × 0.80 = 0.748

        • This shows it is equivalent to 74.8% of the original amount, or a discount of 25.2%

      • 80 × 0.748 = £59.84

  • In general, for n multipliers of values m subscript 1 comma space m subscript 2 comma space... space comma space m subscript n

    • The combined multiplier is m subscript 1 space cross times space m subscript 2 space cross times space... space cross times space m subscript n

How do I find a percentage change?

  • The multiplier that was used for a percentage change can be found using the formula:

    • <img alt=”m equals fraction numerator Amount space after over denominator Amount space before end fraction” data-mathml='<math ><semantics><mrow><mi>m</mi><mo>=</mo><mfrac><mrow><mi>Amount</mi><mo>&#160;</mo><mi>after</mi></mrow><mrow><mi>Amount</mi><mo>&#160;</mo><mi>before</mi></mrow></mfrac></mrow><annotation encoding=”application/vnd.wiris.mtweb-params+json”>{“language”:”en”,”fontFamily”:”Times New Roman”,”fontSize”:”18″,”autoformat”:true}</annotation></semantics></math>’ height=”47″ role=”math” src=”data:image/svg+xml;charset=utf8,%3Csvg%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20xmlns%3Awrs%3D%22http%3A%2F%2Fwww.wiris.com%2Fxml%2Fmathml-extension%22%20height%3D%2247%22%20width%3D%22150%22%20wrs%3Abaseline%3D%2230%22%3E%3C!–MathML%3A%20%3Cmath%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmi%3Em%3C%2Fmi%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmfrac%3E%3Cmrow%3E%3Cmi%3EAmount%3C%2Fmi%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3Eafter%3C%2Fmi%3E%3C%2Fmrow%3E%3Cmrow%3E%3Cmi%3EAmount%3C%2Fmi%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3Ebefore%3C%2Fmi%3E%3C%2Fmrow%3E%3C%2Fmfrac%3E%3C%2Fmath%3E–%3E%3Cdefs%3E%3Cstyle%20type%3D%22text%2Fcss%22%3E%40font-face%7Bfont-family%3A’math17f39f8317fbdb1988ef4c628eb’%3Bsrc%3Aurl(data%3Afont%2Ftruetype%3Bcharset%3Dutf-8%3Bbase64%2CAAEAAAAMAIAAAwBAT1MvMi7iBBMAAADMAAAATmNtYXDEvmKUAAABHAAAADRjdnQgDVUNBwAAAVAAAAA6Z2x5ZoPi2VsAAAGMAAAAsmhlYWQQC2qxAAACQAAAADZoaGVhCGsXSAAAAngAAAAkaG10eE2rRkcAAAKcAAAACGxvY2EAHTwYAAACpAAAAAxtYXhwBT0FPgAAArAAAAAgbmFtZaBxlY4AAALQAAABn3Bvc3QB9wD6AAAEcAAAACBwcmVwa1uragAABJAAAAAUAAADSwGQAAUAAAQABAAAAAAABAAEAAAAAAAAAQEAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACAgICAAAAAg1UADev96AAAD6ACWAAAAAAACAAEAAQAAABQAAwABAAAAFAAEACAAAAAEAAQAAQAAAD3%2F%2FwAAAD3%2F%2F%2F%2FEAAEAAAAAAAABVAMsAIABAABWACoCWAIeAQ4BLAIsAFoBgAKAAKAA1ACAAAAAAAAAACsAVQCAAKsA1QEAASsABwAAAAIAVQAAAwADqwADAAcAADMRIRElIREhVQKr%2FasCAP4AA6v8VVUDAAACAIAA6wLVAhUAAwAHAGUYAbAIELAG1LAGELAF1LAIELAB1LABELAA1LAGELAHPLAFELAEPLABELACPLAAELADPACwCBCwBtSwBhCwB9SwBxCwAdSwARCwAtSwBhCwBTywBxCwBDywARCwADywAhCwAzwxMBMhNSEdASE1gAJV%2FasCVQHAVdVVVQAA

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