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Maths Gcse Edexcel Foundation

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  13. Congruence-Similarity-And-Geometrical-Proof Edexcel Foundation
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  24. Solving-Inequalities Edexcel Foundation
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  26. Graphs-Of-Functions Edexcel Foundation
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  30. Forming-And-Solving-Equations Edexcel Foundation
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  32. Solving-Quadratic-Equations Edexcel Foundation
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  33. Linear-Equations Edexcel Foundation
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  34. Algebraic-Reasoning Edexcel Foundation
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Exam code:1MA1

  • If you know the result of one calculation, you can use it to find the result of a similar, related calculation

  • For example, because 3 × 2 = 6

    • We also know the following:

      • 2 × 3 = 6

      • 6 ÷ 2 = 3

      • 30 × 2 = 60

What are inverse operations?

  • An inverse operation is an operation which undoes another

    • Adding and subtracting are inverses of one another

    • Multiplying and dividing are inverses of one another

  • Inverse operations can be used to help find related calculations

  • For example,

    • If we know that 3 × 5 = 15, then we also know that 15 ÷ 3 = 5 and 15 ÷ 5 = 3

    • If we know that 32 = 9, then we also know that square root of 9 = 3

  • For example, consider the calculation 12 × 13 = 156

  • Using the fact that the order of multiplication does not matter (commutativity)

    • 13 × 12 = 156

    • The order of multiplication and addition does not matter

    • The order of division and subtraction does matter

  • Using inverse operations

    • 156 ÷ 13 = 12

    • 156 ÷ 12 = 13

  • Using multiples of ten

    • Ten times larger

      • 120 × 13 = 1560

    • Ten times smaller

      • 1.2 × 13 = 15.6

    • One value ten times larger, one value 1000 times smaller

      • Answer will therefore be 100 times smaller

      • 0.013 × 120 = 1.56

  • Using a combination of multiples of ten and inverse operations

    • 15 600 ÷ 12

    • = 100 × 156 ÷ 12

    • = 100 × 13

    • = 130

  • If you are dividing by a decimal, use a multiple of ten to change it to an integer first

    • Writing the calculation as a fraction can help

    • Consider 1560 ÷ 1.2

    • fraction numerator 1560 over denominator 1.2 end fraction space equals space 15600 over 12 space equals space fraction numerator 156 space cross times space 100 over denominator 12 end fraction space equals space 13 space cross times space 100 space equals space 1300

Examiner Tips and Tricks

  • Use estimation to check your answer is sensible

  • Rounding numbers to one significant figure can help you estimate the correct order of magnitude

  • E.g. If the answer should be closer to 20 or 2 or 200

Worked Example

Given that 43 × 16 = 688, find the answer to

(i) 688 ÷ 16

Division is the inverse operation to multiplication

If 16 × 43 = 688 then

688 ÷ 16 = 43

43

 (ii) 1.6 × 4300

1.6 is 16 divided by 10

4300 is 43 multiplied by 100

(43 × 100) × (16 ÷ 10)

43 × 16 × 100 ÷ 10

43 × 16 × 10

We know that 43 × 16 = 688

688 × 10

6880

(iii) 68.8 ÷ 4.3

Begin by writing as a fraction and changing the denominator to an integer

fraction numerator 68.8 over denominator 4.3 end fraction space equals space 688 over 43

Division is the inverse operation to multiplication

If 43 × 16 = 688 then 688 ÷ 43 = 16

16

(iv) Explain how you can use estimation to check your answer for part (iii).

Estimate 68.8 ÷ 4.3 by rounding each number to one significant figure

70 ÷ 4 = 17.5

This shows that 16 is likely to be correct, if we had an answer of 1.6 or 160 then we would know we are wrong

We can estimate 68.8 ÷ 4.3 by carrying out the calculation 70 ÷ 4 = 17.5 and comparing our answer

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