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Maths Gcse Aqa Higher

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  1. Scatter-Graphs-And-Correlation Aqa Higher
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  2. Cumulative-Frequency-And-Box-Plots Aqa Higher
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  3. Histograms Aqa Higher
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  4. Statistical-Diagrams Aqa Higher
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  5. Averages-Ranges-And-Data Aqa Higher
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  6. Combined-And-Conditional-Probability Aqa Higher
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  10. Vectors Aqa Higher
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  11. 3D-Pythagoras-And-Trigonometry Aqa Higher
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  12. Sine-Cosine-Rule-And-Area-Of-Triangles Aqa Higher
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  13. Pythagoras-And-Trigonometry Aqa Higher
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  14. Area-And-Volume-Of-Similar-Shapes Aqa Higher
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  27. Ratios Aqa Higher
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  28. Sequences Aqa Higher
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  30. Graphing-Inequalities Aqa Higher
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  32. Real-Life-Graphs Aqa Higher
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  35. Functions Aqa Higher
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  36. Forming-And-Solving-Equations Aqa Higher
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  37. Graphs-Of-Functions Aqa Higher
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  38. Linear-Graphs Aqa Higher
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  44. Algebraic-Proof Aqa Higher
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  55. Introduction Aqa Higher
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Exam code:8300

Linear sequences

What is a linear sequence?

  • A linear sequence goes up (or down) by the same amount each time

  • This amount is called the common difference, d 

    • For example:
      1, 4, 7, 10, 13, …(adding 3, so d = 3)
      15, 10, 5, 0, -5, … (subtracting 5, so d = -5)

  • Linear sequences are also called arithmetic sequences

How do I find the nth term formula for a linear sequence?

  • The formula is n th term = dn + b

    • is the common difference

      • The amount it goes up by each time

    • is the value before the first term (sometimes called the zero term)

      • Imagine going backwards

  • For example 5, 7, 9, 11, ….

    • The sequence adds 2 each time

      • d = 2

    • Now continue the sequence backwards, from 5, by one term

      • (3), 5, 7, 9, 11, …

      • b = 3

    • So the n th term = 2 + 3

  • For example 15, 10, 5, …

    • Subtracting 5 each time means d = -5

    • Going backwards from 15 gives 15 + 5 = 20

      • (20), 15, 10, 5, … so = 20

    • The n th term = -5 + 20

Worked Example

Find a formula for the nth term of the sequence -7, -3, 1, 5, 9, …

The n th term is dn  + b where is the common difference and is the term before the 1st term
The sequence goes up by 4 each time

d = 4

Continue the sequence backwards by one term (-7-4) to find b

(-11), -7, -3, 1, 5, 9, …

= -11

Substitute = 4 and b = -11 into dn  + b

nth term = 4n – 11

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