Maths Gcse Aqa Higher
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Scatter-Graphs-And-Correlation Aqa Higher2 主题
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Cumulative-Frequency-And-Box-Plots Aqa Higher4 主题
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Histograms Aqa Higher3 主题
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Statistical-Diagrams Aqa Higher5 主题
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Averages-Ranges-And-Data Aqa Higher7 主题
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Combined-And-Conditional-Probability Aqa Higher3 主题
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Tree-Diagrams Aqa Higher1 主题
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Simple-Probability-Diagrams Aqa Higher3 主题
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Transformations Aqa Higher5 主题
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Vectors Aqa Higher6 主题
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3D-Pythagoras-And-Trigonometry Aqa Higher1 主题
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Sine-Cosine-Rule-And-Area-Of-Triangles Aqa Higher4 主题
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Pythagoras-And-Trigonometry Aqa Higher4 主题
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Area-And-Volume-Of-Similar-Shapes Aqa Higher1 主题
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Congruence-Similarity-And-Geometrical-Proof Aqa Higher5 主题
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Volume-And-Surface-Area Aqa Higher3 主题
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Circles-Arcs-And-Sectors Aqa Higher2 主题
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Area-And-Perimeter Aqa Higher4 主题
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Circle-Theorems Aqa Higher7 主题
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Bearings-Scale-Drawing-Constructions-And-Loci Aqa Higher5 主题
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Angles-In-Polygons-And-Parallel-Lines Aqa Higher3 主题
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Symmetry-And-Shapes Aqa Higher6 主题
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Exchange-Rates-And-Best-Buys Aqa Higher2 主题
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Standard-And-Compound-Units Aqa Higher5 主题
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Direct-And-Inverse-Proportion Aqa Higher2 主题
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Problem-Solving-With-Ratios Aqa Higher2 主题
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Ratios Aqa Higher3 主题
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Sequences Aqa Higher4 主题
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Transformations-Of-Graphs Aqa Higher2 主题
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Graphing-Inequalities Aqa Higher2 主题
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Solving-Inequalities Aqa Higher2 主题
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Real-Life-Graphs Aqa Higher4 主题
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Estimating-Gradients-And-Areas-Under-Graphs Aqa Higher2 主题
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Equation-Of-A-Circle Aqa Higher2 主题
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Functions Aqa Higher3 主题
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Forming-And-Solving-Equations Aqa Higher3 主题
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Graphs-Of-Functions Aqa Higher6 主题
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Linear-Graphs Aqa Higher4 主题
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Coordinate-Geometry Aqa Higher4 主题
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Iteration Aqa Higher1 主题
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Simultaneous-Equations Aqa Higher2 主题
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Quadratic-Equations Aqa Higher4 主题
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Linear-Equations Aqa Higher1 主题
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Algebraic-Proof Aqa Higher1 主题
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Rearranging-Formulas Aqa Higher2 主题
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Algebraic-Fractions Aqa Higher4 主题
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Completing-The-Square Aqa Higher1 主题
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Factorising Aqa Higher6 主题
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Expanding-Brackets Aqa Higher3 主题
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Algebraic-Roots-And-Indices Aqa Higher1 主题
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Using-A-Calculator Aqa Higher1 主题
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Surds Aqa Higher2 主题
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Rounding-Estimation-And-Bounds Aqa Higher2 主题
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Fractions-Decimals-And-Percentages Aqa Higher3 主题
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Introduction Aqa Higher7 主题
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Simple-And-Compound-Interest-Growth-And-Decay Aqa Higher4 主题
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Percentages Aqa Higher3 主题
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Fractions Aqa Higher4 主题
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Powers-Roots-And-Standard-Form Aqa Higher4 主题
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Prime-Factors-Hcf-And-Lcm Aqa Higher4 主题
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Number-Operations Aqa Higher10 主题
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Product-Rule-For-Counting Aqa Higher
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Systematic-Lists Aqa Higher
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Related-Calculations Aqa Higher
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Multiplication-And-Division Aqa Higher
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Addition-And-Subtraction Aqa Higher
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Money-Calculations Aqa Higher
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Negative-Numbers Aqa Higher
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Irrational-Numbers Aqa Higher
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Order-Of-Operations-Bidmas-Bodmas Aqa Higher
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Mathematical-Symbols Aqa Higher
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Product-Rule-For-Counting Aqa Higher
Multiple-Ratios Aqa Higher
Exam code:8300
Multiple ratios
How do I combine two ratios to make a three-part ratio?
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Identify the link between the two different ratios
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Find equivalent ratios for both original ratios, where the value of the link is the same
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Join the two, two-part ratios into a three-part ratio
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Suppose that on a farm with 85 animals
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The ratio of cows to sheep is 2:3
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The ratio of sheep to pigs is 6:7
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We want to find the number of each animal on the farm
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We need to find a combined, 3-part ratio that shows the relative portions of all the animals together
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Notice that sheep appear in both ratios, so we can use sheep as the link between the two
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C:S = 2:3 and S:P = 6:7
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We can multiply both sides of the C:S ratio by 2, so that both ratios are comparing relative to 6 sheep
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C:S = 4:6 and S:P = 6:7
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These can now be joined together
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C:S:P = 4:6:7
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We can now use this to share the 85 animals in the ratio 4:6:7
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There are 17 parts in total (4 + 6 + 7 = 17)
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Each part is worth 5 animals (85 ÷ 17 = 5)
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There are 20 cows (4 × 5), 30 sheep (6 × 5), and 35 pigs (7 × 5)
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Worked Example
In Jamie’s sock drawer the ratio of black socks to striped socks is 5 : 2 respectively. The ratio of striped socks to white socks in the drawer is 6 : 7 respectively.
Calculate the percentage of socks in the drawer that are black.
Write down the ratios
B : S = 5 : 2
S : W = 6 : 7
S features in both ratios, so we can use it as a link
Multiply the B : S ratio by 3 to find an equivalent ratio
Both ratios are now comparing to 6 striped socks
B : S = 15 : 6
S : W = 6 : 7
Link them together
B : S : W = 15 : 6 : 7
Find the total number of parts
15 + 6 + 7 = 28
This means 15 out of 28 socks are black
Find 15 out of 28 as a decimal by completing the division
Convert to a percentage
Multiply by 100 and round to 3 significant figures
53.6 % of the socks are black
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