Maths Gcse Aqa Higher
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Scatter-Graphs-And-Correlation Aqa Higher2 主题
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Cumulative-Frequency-And-Box-Plots Aqa Higher4 主题
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Histograms Aqa Higher3 主题
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Statistical-Diagrams Aqa Higher5 主题
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Averages-Ranges-And-Data Aqa Higher7 主题
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Combined-And-Conditional-Probability Aqa Higher3 主题
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Tree-Diagrams Aqa Higher1 主题
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Simple-Probability-Diagrams Aqa Higher3 主题
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Transformations Aqa Higher5 主题
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Vectors Aqa Higher6 主题
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3D-Pythagoras-And-Trigonometry Aqa Higher1 主题
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Sine-Cosine-Rule-And-Area-Of-Triangles Aqa Higher4 主题
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Pythagoras-And-Trigonometry Aqa Higher4 主题
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Area-And-Volume-Of-Similar-Shapes Aqa Higher1 主题
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Congruence-Similarity-And-Geometrical-Proof Aqa Higher5 主题
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Volume-And-Surface-Area Aqa Higher3 主题
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Circles-Arcs-And-Sectors Aqa Higher2 主题
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Area-And-Perimeter Aqa Higher4 主题
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Circle-Theorems Aqa Higher7 主题
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Bearings-Scale-Drawing-Constructions-And-Loci Aqa Higher5 主题
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Angles-In-Polygons-And-Parallel-Lines Aqa Higher3 主题
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Symmetry-And-Shapes Aqa Higher6 主题
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Exchange-Rates-And-Best-Buys Aqa Higher2 主题
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Standard-And-Compound-Units Aqa Higher5 主题
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Direct-And-Inverse-Proportion Aqa Higher2 主题
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Problem-Solving-With-Ratios Aqa Higher2 主题
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Ratios Aqa Higher3 主题
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Sequences Aqa Higher4 主题
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Transformations-Of-Graphs Aqa Higher2 主题
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Graphing-Inequalities Aqa Higher2 主题
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Real-Life-Graphs Aqa Higher4 主题
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Estimating-Gradients-And-Areas-Under-Graphs Aqa Higher2 主题
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Equation-Of-A-Circle Aqa Higher2 主题
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Functions Aqa Higher3 主题
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Forming-And-Solving-Equations Aqa Higher3 主题
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Graphs-Of-Functions Aqa Higher6 主题
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Linear-Graphs Aqa Higher4 主题
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Coordinate-Geometry Aqa Higher4 主题
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Iteration Aqa Higher1 主题
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Simultaneous-Equations Aqa Higher2 主题
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Quadratic-Equations Aqa Higher4 主题
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Linear-Equations Aqa Higher1 主题
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Algebraic-Proof Aqa Higher1 主题
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Rearranging-Formulas Aqa Higher2 主题
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Algebraic-Fractions Aqa Higher4 主题
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Completing-The-Square Aqa Higher1 主题
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Factorising Aqa Higher6 主题
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Expanding-Brackets Aqa Higher3 主题
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Algebraic-Roots-And-Indices Aqa Higher1 主题
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Using-A-Calculator Aqa Higher1 主题
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Surds Aqa Higher2 主题
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Rounding-Estimation-And-Bounds Aqa Higher2 主题
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Fractions-Decimals-And-Percentages Aqa Higher3 主题
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Introduction Aqa Higher7 主题
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Simple-And-Compound-Interest-Growth-And-Decay Aqa Higher4 主题
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Percentages Aqa Higher3 主题
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Fractions Aqa Higher4 主题
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Powers-Roots-And-Standard-Form Aqa Higher4 主题
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Prime-Factors-Hcf-And-Lcm Aqa Higher4 主题
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Number-Operations Aqa Higher10 主题
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Product-Rule-For-Counting Aqa Higher
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Systematic-Lists Aqa Higher
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Related-Calculations Aqa Higher
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Multiplication-And-Division Aqa Higher
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Addition-And-Subtraction Aqa Higher
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Money-Calculations Aqa Higher
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Negative-Numbers Aqa Higher
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Irrational-Numbers Aqa Higher
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Order-Of-Operations-Bidmas-Bodmas Aqa Higher
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Mathematical-Symbols Aqa Higher
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Product-Rule-For-Counting Aqa Higher
Related-Calculations Aqa Higher
Exam code:8300
Related calculations
What are related calculations?
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If you know the result of one calculation, you can use it to find the result of a similar, related calculation
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For example, because 3 × 2 = 6
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We also know the following:
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2 × 3 = 6
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6 ÷ 2 = 3
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30 × 2 = 60
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What are inverse operations?
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An inverse operation is an operation which undoes another
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Adding and subtracting are inverses of one another
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Multiplying and dividing are inverses of one another
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Inverse operations can be used to help find related calculations
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For example,
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If we know that 3 × 5 = 15, then we also know that 15 ÷ 3 = 5 and 15 ÷ 5 = 3
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If we know that 32 = 9, then we also know that
= 3
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What types of related calculations are there?
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For example, consider the calculation 12 × 13 = 156
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Using the fact that the order of multiplication does not matter (commutativity)
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13 × 12 = 156
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The order of multiplication and addition does not matter
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The order of division and subtraction does matter
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Using inverse operations
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156 ÷ 13 = 12
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156 ÷ 12 = 13
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Using multiples of ten
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Ten times larger
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120 × 13 = 1560
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Ten times smaller
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1.2 × 13 = 15.6
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One value ten times larger, one value 1000 times smaller
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Answer will therefore be 100 times smaller
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0.013 × 120 = 1.56
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Using a combination of multiples of ten and inverse operations
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15 600 ÷ 12
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= 100 × 156 ÷ 12
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= 100 × 13
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= 130
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If you are dividing by a decimal, use a multiple of ten to change it to an integer first
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Writing the calculation as a fraction can help
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Consider 1560 ÷ 1.2
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Examiner Tips and Tricks
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Use estimation to check your answer is sensible
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Rounding numbers to one significant figure can help you estimate the correct order of magnitude
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E.g. If the answer should be closer to 20 or 2 or 200
Worked Example
Given that 43 × 16 = 688, find the answer to
(i) 688 ÷ 16
Division is the inverse operation to multiplication
If 16 × 43 = 688 then
688 ÷ 16 = 43
43
(ii) 1.6 × 4300
1.6 is 16 divided by 10
4300 is 43 multiplied by 100
(43 × 100) × (16 ÷ 10)
43 × 16 × 100 ÷ 10
43 × 16 × 10
We know that 43 × 16 = 688
688 × 10
6880
(iii) 68.8 ÷ 4.3
Begin by writing as a fraction and changing the denominator to an integer
Division is the inverse operation to multiplication
If 43 × 16 = 688 then 688 ÷ 43 = 16
16
(iv) Explain how you can use estimation to check your answer for part (iii).
Estimate 68.8 ÷ 4.3 by rounding each number to one significant figure
70 ÷ 4 = 17.5
This shows that 16 is likely to be correct, if we had an answer of 1.6 or 160 then we would know we are wrong
We can estimate 68.8 ÷ 4.3 by carrying out the calculation 70 ÷ 4 = 17.5 and comparing our answer
Responses