Maths Gcse Aqa Higher
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Scatter-Graphs-And-Correlation Aqa Higher2 主题
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Cumulative-Frequency-And-Box-Plots Aqa Higher4 主题
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Histograms Aqa Higher3 主题
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Statistical-Diagrams Aqa Higher5 主题
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Averages-Ranges-And-Data Aqa Higher7 主题
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Combined-And-Conditional-Probability Aqa Higher3 主题
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Tree-Diagrams Aqa Higher1 主题
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Simple-Probability-Diagrams Aqa Higher3 主题
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Transformations Aqa Higher5 主题
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Vectors Aqa Higher6 主题
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3D-Pythagoras-And-Trigonometry Aqa Higher1 主题
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Sine-Cosine-Rule-And-Area-Of-Triangles Aqa Higher4 主题
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Pythagoras-And-Trigonometry Aqa Higher4 主题
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Area-And-Volume-Of-Similar-Shapes Aqa Higher1 主题
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Congruence-Similarity-And-Geometrical-Proof Aqa Higher5 主题
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Volume-And-Surface-Area Aqa Higher3 主题
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Circles-Arcs-And-Sectors Aqa Higher2 主题
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Area-And-Perimeter Aqa Higher4 主题
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Circle-Theorems Aqa Higher7 主题
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Bearings-Scale-Drawing-Constructions-And-Loci Aqa Higher5 主题
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Angles-In-Polygons-And-Parallel-Lines Aqa Higher3 主题
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Symmetry-And-Shapes Aqa Higher6 主题
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Exchange-Rates-And-Best-Buys Aqa Higher2 主题
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Standard-And-Compound-Units Aqa Higher5 主题
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Direct-And-Inverse-Proportion Aqa Higher2 主题
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Problem-Solving-With-Ratios Aqa Higher2 主题
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Ratios Aqa Higher3 主题
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Sequences Aqa Higher4 主题
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Transformations-Of-Graphs Aqa Higher2 主题
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Graphing-Inequalities Aqa Higher2 主题
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Solving-Inequalities Aqa Higher2 主题
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Real-Life-Graphs Aqa Higher4 主题
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Estimating-Gradients-And-Areas-Under-Graphs Aqa Higher2 主题
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Equation-Of-A-Circle Aqa Higher2 主题
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Functions Aqa Higher3 主题
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Forming-And-Solving-Equations Aqa Higher3 主题
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Graphs-Of-Functions Aqa Higher6 主题
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Linear-Graphs Aqa Higher4 主题
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Coordinate-Geometry Aqa Higher4 主题
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Iteration Aqa Higher1 主题
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Simultaneous-Equations Aqa Higher2 主题
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Quadratic-Equations Aqa Higher4 主题
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Linear-Equations Aqa Higher1 主题
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Algebraic-Proof Aqa Higher1 主题
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Rearranging-Formulas Aqa Higher2 主题
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Algebraic-Fractions Aqa Higher4 主题
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Completing-The-Square Aqa Higher1 主题
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Factorising Aqa Higher6 主题
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Expanding-Brackets Aqa Higher3 主题
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Algebraic-Roots-And-Indices Aqa Higher1 主题
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Using-A-Calculator Aqa Higher1 主题
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Surds Aqa Higher2 主题
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Rounding-Estimation-And-Bounds Aqa Higher2 主题
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Fractions-Decimals-And-Percentages Aqa Higher3 主题
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Introduction Aqa Higher7 主题
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Simple-And-Compound-Interest-Growth-And-Decay Aqa Higher4 主题
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Percentages Aqa Higher3 主题
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Fractions Aqa Higher4 主题
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Powers-Roots-And-Standard-Form Aqa Higher4 主题
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Prime-Factors-Hcf-And-Lcm Aqa Higher4 主题
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Number-Operations Aqa Higher10 主题
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Product-Rule-For-Counting Aqa Higher
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Systematic-Lists Aqa Higher
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Related-Calculations Aqa Higher
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Multiplication-And-Division Aqa Higher
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Addition-And-Subtraction Aqa Higher
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Money-Calculations Aqa Higher
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Negative-Numbers Aqa Higher
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Irrational-Numbers Aqa Higher
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Order-Of-Operations-Bidmas-Bodmas Aqa Higher
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Mathematical-Symbols Aqa Higher
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Product-Rule-For-Counting Aqa Higher
Combined-Probabilities Aqa Higher
Exam code:8300
Combined probability
How do I calculate combined probabilities?
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You can calculate probabilities of one event after another without needing tree diagrams
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These are called combined (or successive) probabilities
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There are two rules to learn
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And means multiply and or means add
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P(A and B) = P(A) x P(B)
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P(AA or BB) = P(AA) + P(BB)
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Try to rephrase each question using and / or
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For example, when flipping a coin twice:
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P(two heads) = P(head and head)
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P(both the same) = P(head and head or tail and tail) = P(HH) + P(TT)
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Remember that P(not A) = 1 – P(A)
What does independent mean?
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Independent events are events that do not affect each other
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e.g. the probability of rolling a 6 on a fair dice and the probability of getting a head when flipping a coin
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Be careful: questions ‘without replacement’ are not independent
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e.g. the probability of taking a red card out of a pack, not replacing it, then finding the probability of taking a second red card out of the same pack
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The first event affected the number of cards left for the second event
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Worked Example
A box contains 3 blue counters and 8 red counters.
A counter is taken at random and its colour is noted.
The counter is put back into the box.
A second counter is then taken at random, and its colour is noted.
Work out the probability that
(a) both counters are red,
P(both red) = P(red and red)
This is P(red) × P(red) using the ‘and rule’
(b) the two counters are of different colours.
P(different colours) = P(blue and red or red and blue)
This is P(B and R) + P(R and B) using the ‘or rule’
This is P(B) × P(R) + P(R) × P(B) using the ‘and rule’ twice
Responses