Maths Gcse Aqa Higher
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Scatter-Graphs-And-Correlation Aqa Higher2 主题
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Cumulative-Frequency-And-Box-Plots Aqa Higher4 主题
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Histograms Aqa Higher3 主题
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Statistical-Diagrams Aqa Higher5 主题
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Averages-Ranges-And-Data Aqa Higher7 主题
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Combined-And-Conditional-Probability Aqa Higher3 主题
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Tree-Diagrams Aqa Higher1 主题
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Simple-Probability-Diagrams Aqa Higher3 主题
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Transformations Aqa Higher5 主题
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Vectors Aqa Higher6 主题
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3D-Pythagoras-And-Trigonometry Aqa Higher1 主题
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Sine-Cosine-Rule-And-Area-Of-Triangles Aqa Higher4 主题
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Pythagoras-And-Trigonometry Aqa Higher4 主题
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Area-And-Volume-Of-Similar-Shapes Aqa Higher1 主题
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Congruence-Similarity-And-Geometrical-Proof Aqa Higher5 主题
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Volume-And-Surface-Area Aqa Higher3 主题
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Circles-Arcs-And-Sectors Aqa Higher2 主题
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Area-And-Perimeter Aqa Higher4 主题
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Circle-Theorems Aqa Higher7 主题
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Bearings-Scale-Drawing-Constructions-And-Loci Aqa Higher5 主题
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Angles-In-Polygons-And-Parallel-Lines Aqa Higher3 主题
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Symmetry-And-Shapes Aqa Higher6 主题
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Exchange-Rates-And-Best-Buys Aqa Higher2 主题
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Standard-And-Compound-Units Aqa Higher5 主题
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Direct-And-Inverse-Proportion Aqa Higher2 主题
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Problem-Solving-With-Ratios Aqa Higher2 主题
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Ratios Aqa Higher3 主题
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Sequences Aqa Higher4 主题
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Transformations-Of-Graphs Aqa Higher2 主题
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Graphing-Inequalities Aqa Higher2 主题
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Solving-Inequalities Aqa Higher2 主题
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Real-Life-Graphs Aqa Higher4 主题
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Estimating-Gradients-And-Areas-Under-Graphs Aqa Higher2 主题
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Equation-Of-A-Circle Aqa Higher2 主题
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Functions Aqa Higher3 主题
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Forming-And-Solving-Equations Aqa Higher3 主题
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Graphs-Of-Functions Aqa Higher6 主题
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Linear-Graphs Aqa Higher4 主题
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Coordinate-Geometry Aqa Higher4 主题
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Iteration Aqa Higher1 主题
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Simultaneous-Equations Aqa Higher2 主题
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Quadratic-Equations Aqa Higher4 主题
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Linear-Equations Aqa Higher1 主题
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Algebraic-Proof Aqa Higher1 主题
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Rearranging-Formulas Aqa Higher2 主题
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Algebraic-Fractions Aqa Higher4 主题
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Completing-The-Square Aqa Higher1 主题
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Factorising Aqa Higher6 主题
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Expanding-Brackets Aqa Higher3 主题
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Algebraic-Roots-And-Indices Aqa Higher1 主题
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Using-A-Calculator Aqa Higher1 主题
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Surds Aqa Higher2 主题
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Rounding-Estimation-And-Bounds Aqa Higher2 主题
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Fractions-Decimals-And-Percentages Aqa Higher3 主题
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Introduction Aqa Higher7 主题
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Simple-And-Compound-Interest-Growth-And-Decay Aqa Higher4 主题
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Percentages Aqa Higher3 主题
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Fractions Aqa Higher4 主题
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Powers-Roots-And-Standard-Form Aqa Higher4 主题
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Prime-Factors-Hcf-And-Lcm Aqa Higher4 主题
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Number-Operations Aqa Higher10 主题
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Product-Rule-For-Counting Aqa Higher
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Systematic-Lists Aqa Higher
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Related-Calculations Aqa Higher
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Multiplication-And-Division Aqa Higher
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Addition-And-Subtraction Aqa Higher
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Money-Calculations Aqa Higher
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Negative-Numbers Aqa Higher
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Irrational-Numbers Aqa Higher
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Order-Of-Operations-Bidmas-Bodmas Aqa Higher
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Mathematical-Symbols Aqa Higher
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Product-Rule-For-Counting Aqa Higher
Theorems-With-Chords-And-Tangents Aqa Higher
Exam code:8300
Circles & chords
What is a chord?
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A chord is any straight line is a circle that joins any two points on the circumference
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Chords of equal length are equidistant (the same distance) from the centre
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Circle Theorem: The perpendicular bisector of a chord passes through the centre
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If a line through the centre (such as a radius or diameter) goes through the midpoint of chord
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it will bisect (cut in half) that chord at right angles to it
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To spot this circle theorem on a diagram
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look for a radius and see if it intersects any chords
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or look to see if you could draw a radius that bisects a chord
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When explaining this theorem in an exam you can use either phrase below:
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A radius bisects a chord at right angles
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The perpendicular bisector of a chord passes through the centre
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Examiner Tips and Tricks
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Look out for isosceles triangles formed by a chord and two radii
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Two angles in the triangle will be equal and there will be at least one line of symmetry
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Worked Example
The diagram below shows a circle with centre, O.
Two points, P and Q, lie on its circumference.
The radius of the circle is 6 cm.
Angle OPQ = 40º.
Find the length PQ.

Label the radius on the diagram 6 cm
Draw a line from O to the midpoint, M, of the line PQ
The angle formed between the OM and PQ will be a right angle

Use SOHCAHTOA on triangle OMQ to find the length MQ
Double MQ to find the length PQ
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