Back to 课程

Maths Gcse Aqa Foundation

0% Complete
0/0 Steps
  1. Scatter-Graphs-And-Correlation Aqa Foundation
    2 主题
  2. Statistical-Diagrams Aqa Foundation
    6 主题
  3. Averages-Ranges-And-Data Aqa Foundation
    7 主题
  4. Tree-Diagrams-And-Combined-Probability Aqa Foundation
    2 主题
  5. Simple-Probability-Diagrams Aqa Foundation
    4 主题
  6. Transformations Aqa Foundation
    4 主题
  7. Vectors Aqa Foundation
    3 主题
  8. Pythagoras-And-Trigonometry Aqa Foundation
    5 主题
  9. Congruence-Similarity-And-Geometrical-Proof Aqa Foundation
    5 主题
  10. Volume-And-Surface-Area Aqa Foundation
    3 主题
  11. Circles-Arcs-And-Sectors Aqa Foundation
    3 主题
  12. Area-And-Perimeter Aqa Foundation
    4 主题
  13. Bearings-Scale-Drawing-Constructions-And-Loci Aqa Foundation
    5 主题
  14. 2D-And-3D-Shapes Aqa Foundation
    4 主题
  15. Angles-In-Polygons-And-Parallel-Lines Aqa Foundation
    5 主题
  16. Symmetry-And-Shapes Aqa Foundation
    4 主题
  17. Exchange-Rates-And-Best-Buys Aqa Foundation
    2 主题
  18. Standard-And-Compound-Units Aqa Foundation
    5 主题
  19. Direct-And-Inverse-Proportion Aqa Foundation
    1 主题
  20. Ratio-Problem-Solving Aqa Foundation
    2 主题
  21. Sequences Aqa Foundation
    4 主题
  22. Solving-Inequalities Aqa Foundation
    3 主题
  23. Real-Life-Graphs Aqa Foundation
    4 主题
  24. Graphs-Of-Functions Aqa Foundation
    3 主题
  25. Linear-Graphs Aqa Foundation
    3 主题
  26. Coordinate-Geometry Aqa Foundation
    3 主题
  27. Functions Aqa Foundation
    1 主题
  28. Forming-And-Solving-Equations Aqa Foundation
    2 主题
  29. Simultaneous-Equations Aqa Foundation
    1 主题
  30. Solving-Quadratic-Equations Aqa Foundation
    1 主题
  31. Linear-Equations Aqa Foundation
    3 主题
  32. Algebraic-Reasoning Aqa Foundation
    1 主题
  33. Rearranging-Formulas Aqa Foundation
    1 主题
  34. Introduction Aqa Foundation
    10 主题
  35. Factorising Aqa Foundation
    3 主题
  36. Expanding-Brackets Aqa Foundation
    2 主题
  37. Algebraic-Roots-And-Indices Aqa Foundation
    1 主题
  38. Using-A-Calculator Aqa Foundation
    1 主题
  39. Exact-Values Aqa Foundation
    1 主题
  40. Rounding-Estimation-And-Error-Intervals Aqa Foundation
    4 主题
  41. Fractions-Decimals-And-Percentages Aqa Foundation
    2 主题
  42. Simple-And-Compound-Interest-Growth-And-Decay Aqa Foundation
    4 主题
  43. Percentages Aqa Foundation
    5 主题
  44. Fractions Aqa Foundation
    6 主题
  45. Powers-Roots-And-Standard-Form Aqa Foundation
    4 主题
  46. Types-Of-Number-Prime-Factors-Hcf-And-Lcm Aqa Foundation
    6 主题
  47. Number-Operations Aqa Foundation
    9 主题
课 Progress
0% Complete

Exam code:8300

Combined probability

How do I calculate combined probabilities?

  • You can calculate probabilities of one event after another without needing tree diagrams

    • These are called combined (or successive) probabilities

  • There are two rules to learn

    • And means multiply and or means add

    • P(A and B) = P(A) x P(B)

    • P(AA or BB) = P(AA) + P(BB)

  • Try to rephrase each question using and / or

    • For example, when flipping a coin twice: 

      • P(two heads) = P(head and head)

      • P(both the same) = P(head and head or tail and tail) = P(HH) + P(TT)

  • Remember that P(not A) = 1 – P(A)

What does independent mean?

  • Independent events are events that do not affect each other

    • e.g. the probability of rolling a 6 on a fair dice and the probability of getting a head when flipping a coin

  • Be careful: questions ‘without replacement’ are not independent

    • e.g. the probability of taking a red card out of a pack, not replacing it, then finding the probability of taking a second red card out of the same pack

      • The first event affected the number of cards left for the second event

Worked Example

A box contains 3 blue counters and 8 red counters.
A counter is taken at random and its colour is noted.
The counter is put back into the box.
A second counter is then taken at random, and its colour is noted.

Work out the probability that

(a) both counters are red,

P(both red) = P(red and red) 
This is P(red) × P(red) using the ‘and rule’

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 8 over 11 cross times 8 over 11 end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell bold 64 over bold 121 end cell end table

(b) the two counters are of different colours.

P(different colours) = P(blue and red or red and blue)
This is P(B and R) + P(R and B) using the ‘or rule’
This is P(B) × P(R) + P(R) × P(B) using the ‘and rule’ twice

table row blank blank cell 8 over 11 cross times 3 over 11 plus 3 over 11 cross times 8 over 11 end cell row blank equals cell 24 over 121 plus 24 over 121 end cell end table

table row blank blank cell bold 48 over bold 121 end cell end table

Responses

您的邮箱地址不会被公开。 必填项已用 * 标注