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Exam code:9FM0

Oblique collisions with a surface

What are oblique collisions (with a surface)?

  • In a normal collision a particle collides with a surface at right angles

  • In an oblique collision the angle at which the particle collides with the surface is not 90°

  • In oblique collisions

    • there are two dimensions of motion of the particle to consider

    • the velocity of the particle will change and so its momentum will change

    • this is caused by an impulse from the surface to the particle

      • the impulse acts perpendicular to the surface

diagram demonstrating difference between a normal collision and oblique collision

What modelling assumptions are used for oblique collisions?

  • Problems are usually presented with a diagram in plan view (i.e. from above)

  • Modelling assumptions

    • the surface the particle is moving across (‘the floor’) is horizontal

    • the surface the particle will collide with (‘the wall’) is flat and fixed

    • the ‘floor’ and ‘wall’ are smooth (no friction)

    • particles are usually smooth spheres

      • this is so that the impact of the collision can be considered as occurring at a single point in space

What equations are needed to solve oblique collision problems?

diagram of oblique collision with angles and velocity components labelled
  • In the diagram

    • bold u m s-1 is the velocity before impact, bold v m s-1 is the velocity after impact

    • alpha° is the angle of approach, beta° is the angle of rebound

    • bold I N is the impulse (which always acts perpendicular to the surface)

    • e is the coefficient of restitution (between the particle and the surface)

  • The component of velocity parallel to the surface remains unchanged

    • v space cos space beta equals u space cos space alpha

  • The component of velocity perpendicular to the surface can be found by applying Newton’s Law of Restitution

    • table row e equals cell fraction numerator v space sin space beta over denominator u space sin space alpha end fraction end cell end table

    • Rearranging

      • <img alt=”table row cell v space sin space beta end cell equals cell e u space sin space alpha end cell end table” data-mathml='<math ><semantics><mtable columnspacing=”0px” columnalign=”right center left”><mtr><mtd><mi>v</mi><mo> </mo><mi>sin</mi><mo> </mo><mi>β</mi></mtd><mtd><mo>=</mo></mtd><mtd><mi>e</mi><mi>u</mi><mo> </mo><mi>sin</mi><mo> </mo><mi>α</mi></mtd></mtr></mtable><annotation encoding=”application/vnd.wiris.mtweb-params+json”>{“language”:”en”,”fontFamily”:”Times New Roman”,”fontSize”:”18″,”autoformat”:true}</annotation></semantics></math>’ height=”22″ role=”math” src=”data:image/svg+xml;charset=utf8,%3Csvg%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20xmlns%3Awrs%3D%22http%3A%2F%2Fwww.wiris.com%2Fxml%2Fmathml-extension%22%20height%3D%2222%22%20width%3D%22124%22%20wrs%3Abaseline%3D%2216%22%3E%3C!–MathML%3A%20%3Cmath%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmtable%20columnalign%3D%22right%20center%20left%22%20columnspacing%3D%220px%22%3E%3Cmtr%3E%3Cmtd%3E%3Cmi%3Ev%3C%2Fmi%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3Esin%3C%2Fmi%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3E%26%23x3B2%3B%3C%2Fmi%3E%3C%2Fmtd%3E%3Cmtd%3E%3Cmo%3E%3D%3C%2Fmo%3E%3C%2Fmtd%3E%3Cmtd%3E%3Cmi%3Ee%3C%2Fmi%3E%3Cmi%3Eu%3C%2Fmi%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3Esin%3C%2Fmi%3E%3Cmo%3E%26%23xA0%3B%3C%2Fmo%3E%3Cmi%3E%26%

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