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Further Maths: Core Pure -Edexcel-A Level

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  1. complex-numbers-and-argand-diagrams
    6 主题
  2. exponential-form-and-de-moivres-theorem
    4 主题
  3. properties-of-matrices
    3 主题
  4. transformations-using-matrices
    3 主题
  5. roots-of-polynomials
    2 主题
  6. series
    2 主题
  7. maclaurin-series
    1 主题
  8. hyperbolic-functions
    4 主题
  9. volumes-of-revolution
    2 主题
  10. methods-in-calculus
    5 主题
  11. vector-lines
    4 主题
  12. vector-planes
    4 主题
  13. polar-coordinates
    2 主题
  14. first-order-differential-equations
    3 主题
  15. second-order-differential-equations
    2 主题
  16. simple-harmonic-motion
    2 主题
  17. proof-by-induction
    2 主题
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Shortest distance between a point & a line

How do I find the shortest distance from a point to a line?

  • The shortest distance from any point to a line will always be the perpendicular distance

    • Given a line l with equation bold r bold space equals bold space bold a plus straight lambda bold b and a point P not on l

    • The scalar product of the direction vector, b, and the vector in the direction of the shortest distance will be zero

  • The shortest distance can be found using the following steps:

    • STEP 1: Let the vector equation of the line be r and the point not on the line be P, then the point on the line closest to P will be the point F

      • The point F is sometimes called the foot of the perpendicular

    • STEP 2: Sketch a diagram showing the line l and the points P and F

      • The vector stack F P with rightwards arrow on top will be perpendicular to the line l

    • STEP 3: Use the equation of the line to find the position vector of the point F in terms of λ

    • STEP 4: Use this to find the displacement vector stack F P with rightwards arrow on top in terms of λ

    • STEP 5: The scalar product of the direction vector of the line l and the displacement vector stack F P with rightwards arrow on top will be zero

      • Form an equation stack F P with rightwards arrow on top times bold b equals 0 and so

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