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Exam code:8BN0

1.2.11 Practical: Vitamin C Content

  • Vitamin C is found in green vegetables, fruits, and potatoes

  • It is essential for a healthy diet

  • The chemical name for vitamin C is ascorbic acid

    • Ascorbic acid is a good reducing agent and therefore it is easily oxidised

  • Methods for the detection of vitamin C involve titrating it against a solution of an oxidising agent called DCPIP

    • DCPIP is a blue dye that turns colourless in the presence of vitamin C

    • Note that titration is a method of chemical analysis that involves determining the quantity of a substance present by gradually adding another substance

Apparatus

  • Vitamin C solutions

  • 1% DCPIP solution

  • Distilled water

  • Range of fruit juices

  • Measuring cylinder

  • Pipette

  • Stop watch

  • Test tubes

Method

  1. Make up a series. e.g. six, of known vitamin C concentrations

    • This can be done by serial dilution

  2. Use a measuring cylinder to measure out 1 cm3 of DCPIP solution into a test tube

  3. Add one of the vitamin C solutions, drop by drop, to the DCPIP solution using a graduated pipette or burette

    • Shake the tube for a set period of time after adding each drop

    • It is important to keep the shaking time the same for each concentration; this is a control variable

  4. When the solution turns colourless record the volume of vitamin C solution added

  5. Repeat steps 2-4 for the same concentration twice more and calculate a mean

  6. Repeat steps 2-5 for each of the known concentrations

  7. Results can be plotted as a line of best fit showing the volume of vitamin C needed to decolourise DCPIP against the concentration of vitamin C

    • This is a calibration curve and can be used to find the concentration of vitamin C in unknown samples such as fruit juices

  8. Repeat steps 2-6 using fruit juices of unknown concentration; these can be compared to the calibration curve to estimate concentration of vitamin C in each juice sample

Risk assessment

  • DCPIP is an irritant 

    • Avoid contact with the skin 

    • Wear eye protection

The DCPIP test for Vitamin C

Drops of vitamin C solution of known concentration can be added to DCPIP to determine the volume required for the DCPIP to be decolourised

Results

  • The volume of vitamin C solution required to decolourise DCPIP should decrease as the concentration of the vitamin C solution increases

  • The results of the experiment can be plotted on a graph of volume of vitamin C needed to decolourise DCPIP against the concentration of vitamin C

    • The line of best fit for such a graph is known as a calibration curve; unknown substances can be compared to it to gain an estimate of their vitamin C concentration

  • This calibration curve produced from this experiment can be used to estimate the concentration of vitamin C in fruit juices 

vitamin-c-dcpip-results

A graph of volume of vitamin C needed to decolourise DCPIP against vitamin C concentration can be used as a calibration curve to estimate the vitamin C concentration of unknown substances

Calculating the mass of vitamin C

  • It is possible to use the results of the practical described above to calculate the mass of vitamin C present at various points in the investigation

    • This is because we know that 1 cm³ of 1 % vitamin C solution contains 10 mg of vitamin C

  • The mass of vitamin C needed to decolourise DCPIP can be calculated as follows:

mass of vitamin C to decolourise 1cm³ of DCPIP = 10 mg × volume of vitamin C used

  • Calculating the mass of vitamin C needed to decolourise DCPIP then allows us to calculate the mass of vitamin C present in a fruit juice sample:

mass of vitamin C in fruit juice sample = mass of vitamin C to decolourise 1cm³ of DCPIP × volume of fruit juice used

Worked Example

In an investigation into vitamin C concentration a mean of 0.6 cm3 of a 1 % vitamin C solution was needed to decolourise a 1 cm3 DCPIP sample. A mean of 1.4 cm3 of a fruit juice was needed to decolourise the same volume of DCPIP.

Calculate the mass of vitamin C needed to decolourise 1 cm3 DCPIP, and the mass of DCPIP present in the fruit juice sample.

Answer:

Step 1: calculate the mass of vitamin C needed to decolorise 1 cm3 DCPIP

mass to decolourise DCPIP = 10 mg × volume of vitamin C used 

= 10 x 0.6

= 6 mg

Step 2: calculate the mass of vitamin C in the fruit juice sample

mass in fruit juice sample = mass of vitamin C to decolourise 1cm³ of DCPIP × volume of fruit juice used

= 6 x 1.4

= 8.4 mg

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