Back to 课程

Biology AS CIE

0% Complete
0/0 Steps
  1. 1-cell-structure
    10 主题
  2. 2-biological-molecules
    19 主题
  3. 3-enzymes
    13 主题
  4. 4-cell-membranes-and-transport
    16 主题
  5. 5-the-mitotic-cell-cycle
    8 主题
  6. 6-nucleic-acids-and-protein-synthesis
    9 主题
  7. 7-transport-in-plants
    11 主题
  8. 8-transport-in-mammals
    16 主题
  9. 9-gas-exchange
    6 主题
  10. 10-infectious-diseases
    6 主题
  11. 11-immunity
    10 主题
课 4, 主题 6
In Progress

4-2-movement-into-and-out-of-cells AS surface-area-to-volume-ratios

课 Progress
0% Complete

Exam code:9700

Principles of SA:V

  • Surface area and volume are both very important factors in the exchange of materials in organisms

  • As the surface area and volume of an organism increase (and therefore the overall ‘size’ of the organism increases), the surface area : volume ratio decreases

  • This is because volume increases more rapidly than surface area as size increases

Importance of a high surface area to volume ratio

  • Having a high surface area to volume ratio increases the ability of a biological system to perform the following important functions

    • Obtaining necessary resources eg, oxygen, glucose, amino acids

    • Eliminating waste products eg. carbon dioxide, urea

    • Acquiring or dissipating thermal energy (heat)

    • Otherwise exchanging chemicals and energy with the surroundings eg. absorbing hormones at the cell surface in the hormone’s target organ

Three cubes with side lengths of 1 cm, 2 cm, and 3 cm; table of their surface areas, volumes, and surface area-to-volume ratios below.
As size increases, the surface area : volume ratio decreases

 

Cube

Cuboid

Cylinder

 Diagram

cube-all-sides-length-s
cuboid-with-length-width-height-showing
cylinder-with-radius-height-showing

Surface Area

6s2

2lh + 2lw + 2wh

1x rectangle = 2πrh

2x circular ends = 2πr2

SA = 2πrh + 2πr2

Volume

s3

l × w × h

πr2h

Example

If s = 1 cm then SA = (1×1)×6 SA = 6cm2

V = s3 = 13 =1cm3 ∴ SA:V ratio = 6:1

If l = 4cm, w = 2cm, h = 1cm, then SA = 2((4×1)+(4×2)+(2×1)) = 28cm2

V = 4 × 2 × 1 = 8cm3

∴ SA:V ratio = 28:8 = 3.5:1

If r = 2 cm and h = 6cm, then SA = 2πrh + 2πr2 = 8π +24π = 32π cm2

V = π(2)2 × 6 = 24π cm2

∴ SA : V ratio = 32 : 24 = 1.33:1

Worked Example

Calculate the surface area-to-volume ratios of the two following microorganisms:

  1. A bacterial cell from the species Staphylococcus aureus; you can assume that each cell is a cube with side length of 800 nm (8 × 10-9 m)

  2. A bacterial cell from the species Bacillus subtilis; these are rod-shaped cells which you can assume to be cylindrical in shape. They are 5 µm long and 1 µm in diameter

Comment on your calculated answers. 

Solution

1. For the Staphylococcus aureus cell: side length = 800 nm

Convert this value into µm by dividing by 1000

fraction numerator 800 space nm over denominator 1000 end fraction equals space 0.8 straight mu straight m

Surface area of cube = 6(s2)

= 6 × (0.8 × 0.8) = 3.84 µm2

Volume = 0.8 × 0.8 × 0.8

= 0.512 µm3

A ratio is one number divided by another with the larger number divided by the smaller number, so

<img alt=”SA colon straight V space ratio space equals space fraction numerator 3.84 over denominator 0.512 end fraction equals fraction numerator 7.5 over denominator 1 end fraction equals 7.5 space colon space 1 space open parentheses or space simply space 7.5 close parentheses” data-mathml='<math style=”font-family:Arial” ><semantics><mrow><mi>SA</mi><mo>:</mo><mi mathvariant=”normal”>V</mi><mo> </mo><mi>ratio</mi><mo> </mo><mo>=</mo><mo> </mo><mfrac><mrow><mn>3</mn><mo>.</mo><mn>84</mn></mrow><mrow><mn>0</mn><mo>.</mo><mn>512</mn></mrow></mfrac><mo>=</mo><mfrac><mrow><mn>7</mn><mo>.</mo><mn>5</mn></mrow><mn>1</mn></mfrac><mo>=</mo><mn>7</mn><mo>.</mo><mn>5</mn><mo> </mo><mo>:</mo><mo> </mo><mn>1</mn><mo> </mo><mfenced><mrow><mi>or</mi><mo> </mo><mi>simply</mi><mo> </mo><mn>7</mn><mo>.</mo><mn>5</mn></mrow></mfenced></mrow><annotation encoding=”application/vnd.wiris.mtweb-params+json”>{“language”:”en”,”fontFamily”:”Times New Roman”,”fontSize”:”18″,”autoformat”:true}</annotation></semantics></math>’ height=”49″ role=”math” src=”data:image/svg+xml;charset=utf8,%3Csvg%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20xmlns%3Awrs%3D%22http%3A%2F%2Fwww.wiris.com%2Fxml%2Fmathml-extension%22%20height%3D%2249%22%20width%3D%22410%22%20wrs%3Abaseline%3D%2231%22%3E%3C!–MathML%3A%20%3Cmath%20xmlns%3D%22http%3A%2F%2Fwww.w3.or

Responses

您的邮箱地址不会被公开。 必填项已用 * 标注